Optimal. Leaf size=102 \[ -\frac {2 e}{d (c d-b e) \sqrt {d+e x}}-\frac {2 \tanh ^{-1}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )}{b d^{3/2}}+\frac {2 c^{3/2} \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {d+e x}}{\sqrt {c d-b e}}\right )}{b (c d-b e)^{3/2}} \]
[Out]
________________________________________________________________________________________
Rubi [A]
time = 0.20, antiderivative size = 102, normalized size of antiderivative = 1.00, number of steps
used = 5, number of rules used = 4, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {723, 840, 1180,
214} \begin {gather*} \frac {2 c^{3/2} \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {d+e x}}{\sqrt {c d-b e}}\right )}{b (c d-b e)^{3/2}}-\frac {2 e}{d \sqrt {d+e x} (c d-b e)}-\frac {2 \tanh ^{-1}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )}{b d^{3/2}} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
Rule 214
Rule 723
Rule 840
Rule 1180
Rubi steps
\begin {align*} \int \frac {1}{(d+e x)^{3/2} \left (b x+c x^2\right )} \, dx &=-\frac {2 e}{d (c d-b e) \sqrt {d+e x}}+\frac {\int \frac {c d-b e-c e x}{\sqrt {d+e x} \left (b x+c x^2\right )} \, dx}{d (c d-b e)}\\ &=-\frac {2 e}{d (c d-b e) \sqrt {d+e x}}+\frac {2 \text {Subst}\left (\int \frac {c d e+e (c d-b e)-c e x^2}{c d^2-b d e+(-2 c d+b e) x^2+c x^4} \, dx,x,\sqrt {d+e x}\right )}{d (c d-b e)}\\ &=-\frac {2 e}{d (c d-b e) \sqrt {d+e x}}+\frac {(2 c) \text {Subst}\left (\int \frac {1}{-\frac {b e}{2}+\frac {1}{2} (-2 c d+b e)+c x^2} \, dx,x,\sqrt {d+e x}\right )}{b d}-\frac {\left (2 c^2\right ) \text {Subst}\left (\int \frac {1}{\frac {b e}{2}+\frac {1}{2} (-2 c d+b e)+c x^2} \, dx,x,\sqrt {d+e x}\right )}{b (c d-b e)}\\ &=-\frac {2 e}{d (c d-b e) \sqrt {d+e x}}-\frac {2 \tanh ^{-1}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )}{b d^{3/2}}+\frac {2 c^{3/2} \tanh ^{-1}\left (\frac {\sqrt {c} \sqrt {d+e x}}{\sqrt {c d-b e}}\right )}{b (c d-b e)^{3/2}}\\ \end {align*}
________________________________________________________________________________________
Mathematica [A]
time = 0.30, size = 102, normalized size = 1.00 \begin {gather*} \frac {2 e}{d (-c d+b e) \sqrt {d+e x}}+\frac {2 c^{3/2} \tan ^{-1}\left (\frac {\sqrt {c} \sqrt {d+e x}}{\sqrt {-c d+b e}}\right )}{b (-c d+b e)^{3/2}}-\frac {2 \tanh ^{-1}\left (\frac {\sqrt {d+e x}}{\sqrt {d}}\right )}{b d^{3/2}} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [A]
time = 0.43, size = 103, normalized size = 1.01
method | result | size |
derivativedivides | \(2 e \left (-\frac {\arctanh \left (\frac {\sqrt {e x +d}}{\sqrt {d}}\right )}{d^{\frac {3}{2}} b e}+\frac {c^{2} \arctan \left (\frac {c \sqrt {e x +d}}{\sqrt {\left (b e -c d \right ) c}}\right )}{\left (b e -c d \right ) b e \sqrt {\left (b e -c d \right ) c}}+\frac {1}{d \left (b e -c d \right ) \sqrt {e x +d}}\right )\) | \(103\) |
default | \(2 e \left (-\frac {\arctanh \left (\frac {\sqrt {e x +d}}{\sqrt {d}}\right )}{d^{\frac {3}{2}} b e}+\frac {c^{2} \arctan \left (\frac {c \sqrt {e x +d}}{\sqrt {\left (b e -c d \right ) c}}\right )}{\left (b e -c d \right ) b e \sqrt {\left (b e -c d \right ) c}}+\frac {1}{d \left (b e -c d \right ) \sqrt {e x +d}}\right )\) | \(103\) |
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 183 vs.
\(2 (91) = 182\).
time = 1.79, size = 766, normalized size = 7.51 \begin {gather*} \left [-\frac {2 \, \sqrt {x e + d} b d e + {\left (c d^{2} x e + c d^{3}\right )} \sqrt {\frac {c}{c d - b e}} \log \left (\frac {2 \, c d - 2 \, {\left (c d - b e\right )} \sqrt {x e + d} \sqrt {\frac {c}{c d - b e}} + {\left (c x - b\right )} e}{c x + b}\right ) - {\left (c d^{2} - b x e^{2} + {\left (c d x - b d\right )} e\right )} \sqrt {d} \log \left (\frac {x e - 2 \, \sqrt {x e + d} \sqrt {d} + 2 \, d}{x}\right )}{b c d^{4} - b^{2} d^{2} x e^{2} + {\left (b c d^{3} x - b^{2} d^{3}\right )} e}, -\frac {2 \, \sqrt {x e + d} b d e - 2 \, {\left (c d^{2} x e + c d^{3}\right )} \sqrt {-\frac {c}{c d - b e}} \arctan \left (-\frac {{\left (c d - b e\right )} \sqrt {x e + d} \sqrt {-\frac {c}{c d - b e}}}{c x e + c d}\right ) - {\left (c d^{2} - b x e^{2} + {\left (c d x - b d\right )} e\right )} \sqrt {d} \log \left (\frac {x e - 2 \, \sqrt {x e + d} \sqrt {d} + 2 \, d}{x}\right )}{b c d^{4} - b^{2} d^{2} x e^{2} + {\left (b c d^{3} x - b^{2} d^{3}\right )} e}, -\frac {2 \, \sqrt {x e + d} b d e - 2 \, {\left (c d^{2} - b x e^{2} + {\left (c d x - b d\right )} e\right )} \sqrt {-d} \arctan \left (\frac {\sqrt {x e + d} \sqrt {-d}}{d}\right ) + {\left (c d^{2} x e + c d^{3}\right )} \sqrt {\frac {c}{c d - b e}} \log \left (\frac {2 \, c d - 2 \, {\left (c d - b e\right )} \sqrt {x e + d} \sqrt {\frac {c}{c d - b e}} + {\left (c x - b\right )} e}{c x + b}\right )}{b c d^{4} - b^{2} d^{2} x e^{2} + {\left (b c d^{3} x - b^{2} d^{3}\right )} e}, -\frac {2 \, {\left (\sqrt {x e + d} b d e - {\left (c d^{2} x e + c d^{3}\right )} \sqrt {-\frac {c}{c d - b e}} \arctan \left (-\frac {{\left (c d - b e\right )} \sqrt {x e + d} \sqrt {-\frac {c}{c d - b e}}}{c x e + c d}\right ) - {\left (c d^{2} - b x e^{2} + {\left (c d x - b d\right )} e\right )} \sqrt {-d} \arctan \left (\frac {\sqrt {x e + d} \sqrt {-d}}{d}\right )\right )}}{b c d^{4} - b^{2} d^{2} x e^{2} + {\left (b c d^{3} x - b^{2} d^{3}\right )} e}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [A]
time = 6.24, size = 94, normalized size = 0.92 \begin {gather*} \frac {2 e}{d \sqrt {d + e x} \left (b e - c d\right )} + \frac {2 c \operatorname {atan}{\left (\frac {\sqrt {d + e x}}{\sqrt {\frac {b e - c d}{c}}} \right )}}{b \sqrt {\frac {b e - c d}{c}} \left (b e - c d\right )} + \frac {2 \operatorname {atan}{\left (\frac {\sqrt {d + e x}}{\sqrt {- d}} \right )}}{b d \sqrt {- d}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [A]
time = 1.27, size = 113, normalized size = 1.11 \begin {gather*} -\frac {2 \, c^{2} \arctan \left (\frac {\sqrt {x e + d} c}{\sqrt {-c^{2} d + b c e}}\right )}{{\left (b c d - b^{2} e\right )} \sqrt {-c^{2} d + b c e}} - \frac {2 \, e}{{\left (c d^{2} - b d e\right )} \sqrt {x e + d}} + \frac {2 \, \arctan \left (\frac {\sqrt {x e + d}}{\sqrt {-d}}\right )}{b \sqrt {-d} d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Mupad [B]
time = 0.63, size = 2258, normalized size = 22.14 \begin {gather*} -\frac {2\,e}{\left (c\,d^2-b\,d\,e\right )\,\sqrt {d+e\,x}}-\frac {2\,\mathrm {atanh}\left (\frac {48\,c^7\,d^7\,e^3\,\sqrt {d+e\,x}}{\sqrt {d^3}\,\left (-16\,b^5\,c^2\,d\,e^8+96\,b^4\,c^3\,d^2\,e^7-240\,b^3\,c^4\,d^3\,e^6+304\,b^2\,c^5\,d^4\,e^5-192\,b\,c^6\,d^5\,e^4+48\,c^7\,d^6\,e^3\right )}-\frac {192\,b\,c^6\,d^6\,e^4\,\sqrt {d+e\,x}}{\sqrt {d^3}\,\left (-16\,b^5\,c^2\,d\,e^8+96\,b^4\,c^3\,d^2\,e^7-240\,b^3\,c^4\,d^3\,e^6+304\,b^2\,c^5\,d^4\,e^5-192\,b\,c^6\,d^5\,e^4+48\,c^7\,d^6\,e^3\right )}+\frac {304\,b^2\,c^5\,d^5\,e^5\,\sqrt {d+e\,x}}{\sqrt {d^3}\,\left (-16\,b^5\,c^2\,d\,e^8+96\,b^4\,c^3\,d^2\,e^7-240\,b^3\,c^4\,d^3\,e^6+304\,b^2\,c^5\,d^4\,e^5-192\,b\,c^6\,d^5\,e^4+48\,c^7\,d^6\,e^3\right )}-\frac {240\,b^3\,c^4\,d^4\,e^6\,\sqrt {d+e\,x}}{\sqrt {d^3}\,\left (-16\,b^5\,c^2\,d\,e^8+96\,b^4\,c^3\,d^2\,e^7-240\,b^3\,c^4\,d^3\,e^6+304\,b^2\,c^5\,d^4\,e^5-192\,b\,c^6\,d^5\,e^4+48\,c^7\,d^6\,e^3\right )}+\frac {96\,b^4\,c^3\,d^3\,e^7\,\sqrt {d+e\,x}}{\sqrt {d^3}\,\left (-16\,b^5\,c^2\,d\,e^8+96\,b^4\,c^3\,d^2\,e^7-240\,b^3\,c^4\,d^3\,e^6+304\,b^2\,c^5\,d^4\,e^5-192\,b\,c^6\,d^5\,e^4+48\,c^7\,d^6\,e^3\right )}-\frac {16\,b^5\,c^2\,d^2\,e^8\,\sqrt {d+e\,x}}{\sqrt {d^3}\,\left (-16\,b^5\,c^2\,d\,e^8+96\,b^4\,c^3\,d^2\,e^7-240\,b^3\,c^4\,d^3\,e^6+304\,b^2\,c^5\,d^4\,e^5-192\,b\,c^6\,d^5\,e^4+48\,c^7\,d^6\,e^3\right )}\right )}{b\,\sqrt {d^3}}+\frac {\mathrm {atan}\left (\frac {\frac {\sqrt {-c^3\,{\left (b\,e-c\,d\right )}^3}\,\left (\sqrt {d+e\,x}\,\left (-8\,b^5\,c^3\,d^3\,e^7+40\,b^4\,c^4\,d^4\,e^6-88\,b^3\,c^5\,d^5\,e^5+104\,b^2\,c^6\,d^6\,e^4-64\,b\,c^7\,d^7\,e^3+16\,c^8\,d^8\,e^2\right )-\frac {\sqrt {-c^3\,{\left (b\,e-c\,d\right )}^3}\,\left (72\,b^3\,c^6\,d^8\,e^4-16\,b^2\,c^7\,d^9\,e^3-128\,b^4\,c^5\,d^7\,e^5+112\,b^5\,c^4\,d^6\,e^6-48\,b^6\,c^3\,d^5\,e^7+8\,b^7\,c^2\,d^4\,e^8+\frac {\sqrt {-c^3\,{\left (b\,e-c\,d\right )}^3}\,\sqrt {d+e\,x}\,\left (8\,b^8\,c^2\,d^5\,e^8-56\,b^7\,c^3\,d^6\,e^7+160\,b^6\,c^4\,d^7\,e^6-240\,b^5\,c^5\,d^8\,e^5+200\,b^4\,c^6\,d^9\,e^4-88\,b^3\,c^7\,d^{10}\,e^3+16\,b^2\,c^8\,d^{11}\,e^2\right )}{b\,{\left (b\,e-c\,d\right )}^3}\right )}{b\,{\left (b\,e-c\,d\right )}^3}\right )\,1{}\mathrm {i}}{b\,{\left (b\,e-c\,d\right )}^3}+\frac {\sqrt {-c^3\,{\left (b\,e-c\,d\right )}^3}\,\left (\sqrt {d+e\,x}\,\left (-8\,b^5\,c^3\,d^3\,e^7+40\,b^4\,c^4\,d^4\,e^6-88\,b^3\,c^5\,d^5\,e^5+104\,b^2\,c^6\,d^6\,e^4-64\,b\,c^7\,d^7\,e^3+16\,c^8\,d^8\,e^2\right )-\frac {\sqrt {-c^3\,{\left (b\,e-c\,d\right )}^3}\,\left (16\,b^2\,c^7\,d^9\,e^3-72\,b^3\,c^6\,d^8\,e^4+128\,b^4\,c^5\,d^7\,e^5-112\,b^5\,c^4\,d^6\,e^6+48\,b^6\,c^3\,d^5\,e^7-8\,b^7\,c^2\,d^4\,e^8+\frac {\sqrt {-c^3\,{\left (b\,e-c\,d\right )}^3}\,\sqrt {d+e\,x}\,\left (8\,b^8\,c^2\,d^5\,e^8-56\,b^7\,c^3\,d^6\,e^7+160\,b^6\,c^4\,d^7\,e^6-240\,b^5\,c^5\,d^8\,e^5+200\,b^4\,c^6\,d^9\,e^4-88\,b^3\,c^7\,d^{10}\,e^3+16\,b^2\,c^8\,d^{11}\,e^2\right )}{b\,{\left (b\,e-c\,d\right )}^3}\right )}{b\,{\left (b\,e-c\,d\right )}^3}\right )\,1{}\mathrm {i}}{b\,{\left (b\,e-c\,d\right )}^3}}{16\,c^7\,d^6\,e^3-48\,b\,c^6\,d^5\,e^4+48\,b^2\,c^5\,d^4\,e^5-16\,b^3\,c^4\,d^3\,e^6+\frac {\sqrt {-c^3\,{\left (b\,e-c\,d\right )}^3}\,\left (\sqrt {d+e\,x}\,\left (-8\,b^5\,c^3\,d^3\,e^7+40\,b^4\,c^4\,d^4\,e^6-88\,b^3\,c^5\,d^5\,e^5+104\,b^2\,c^6\,d^6\,e^4-64\,b\,c^7\,d^7\,e^3+16\,c^8\,d^8\,e^2\right )-\frac {\sqrt {-c^3\,{\left (b\,e-c\,d\right )}^3}\,\left (72\,b^3\,c^6\,d^8\,e^4-16\,b^2\,c^7\,d^9\,e^3-128\,b^4\,c^5\,d^7\,e^5+112\,b^5\,c^4\,d^6\,e^6-48\,b^6\,c^3\,d^5\,e^7+8\,b^7\,c^2\,d^4\,e^8+\frac {\sqrt {-c^3\,{\left (b\,e-c\,d\right )}^3}\,\sqrt {d+e\,x}\,\left (8\,b^8\,c^2\,d^5\,e^8-56\,b^7\,c^3\,d^6\,e^7+160\,b^6\,c^4\,d^7\,e^6-240\,b^5\,c^5\,d^8\,e^5+200\,b^4\,c^6\,d^9\,e^4-88\,b^3\,c^7\,d^{10}\,e^3+16\,b^2\,c^8\,d^{11}\,e^2\right )}{b\,{\left (b\,e-c\,d\right )}^3}\right )}{b\,{\left (b\,e-c\,d\right )}^3}\right )}{b\,{\left (b\,e-c\,d\right )}^3}-\frac {\sqrt {-c^3\,{\left (b\,e-c\,d\right )}^3}\,\left (\sqrt {d+e\,x}\,\left (-8\,b^5\,c^3\,d^3\,e^7+40\,b^4\,c^4\,d^4\,e^6-88\,b^3\,c^5\,d^5\,e^5+104\,b^2\,c^6\,d^6\,e^4-64\,b\,c^7\,d^7\,e^3+16\,c^8\,d^8\,e^2\right )-\frac {\sqrt {-c^3\,{\left (b\,e-c\,d\right )}^3}\,\left (16\,b^2\,c^7\,d^9\,e^3-72\,b^3\,c^6\,d^8\,e^4+128\,b^4\,c^5\,d^7\,e^5-112\,b^5\,c^4\,d^6\,e^6+48\,b^6\,c^3\,d^5\,e^7-8\,b^7\,c^2\,d^4\,e^8+\frac {\sqrt {-c^3\,{\left (b\,e-c\,d\right )}^3}\,\sqrt {d+e\,x}\,\left (8\,b^8\,c^2\,d^5\,e^8-56\,b^7\,c^3\,d^6\,e^7+160\,b^6\,c^4\,d^7\,e^6-240\,b^5\,c^5\,d^8\,e^5+200\,b^4\,c^6\,d^9\,e^4-88\,b^3\,c^7\,d^{10}\,e^3+16\,b^2\,c^8\,d^{11}\,e^2\right )}{b\,{\left (b\,e-c\,d\right )}^3}\right )}{b\,{\left (b\,e-c\,d\right )}^3}\right )}{b\,{\left (b\,e-c\,d\right )}^3}}\right )\,\sqrt {-c^3\,{\left (b\,e-c\,d\right )}^3}\,2{}\mathrm {i}}{b\,{\left (b\,e-c\,d\right )}^3} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________